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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

A 500 g ball is released from a height of 4 m . Each time it makes contact with the ground, it loses 25 % of its kinetic energy. Find the kinetic energy it possess just after the 3 r d hit

Options

  1. A15 J
  2. B11.25 J
  3. C8.44 J
  4. Dnone of these

Correct answer

C. 8.44 J

Step-by-step solution

After first hit K . E 1 = e 2 K . E 3 / 4 K . E = e 2 K . E ⇒ e 2 = 3 / 4 K . E . a f t e r t h i r d h i t = ( e 2 ) 3 K E = 27 64 m g h = 27 64 1 2 . 10.4 = 27 5 16 = 135 16 = 8.44 J

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