NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice
Three point masses 1 . 0 kg , 1 . 5 kg and 2 . 5 kg are placed at the vertices of a right-angle triangle of sides 4 . 0 cm , 3 . 0 cm and 5 . 0 cm , as shown in the figure. The centre of mass of the system is
Options
- A0 . 6 cm right and 2 . 0 cm above 1 kg mass
- B2 . 0 cm right and 0 . 9 cm above 1 kg mass
- C0 . 9 cm right and 2 . 0 cm above 1 kg mass
- D1 . 5 cm right and 1 . 2 cm above 1 kg mass
Correct answer
C. 0 . 9 cm right and 2 . 0 cm above 1 kg mass
Step-by-step solution
Let us assume that the origin of the coordinate system is at the location of 1 kg mass, then x cm = 1 × 0 + 1 . 5 × 3 + 2 . 5 × 0 5 = 0 . 9   cm y cm = 1 × 0 + 1 . 5 × 0 + 2 . 5 × 4 5 = 2   cm