NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice
A machine gun fires a bullet of mass 40 g with a velocity 1200 m s - 1 . The man holding it can exert a maximum force of 144 N on the gun. The maximum number of bullets that the man can fire per second is
Correct answer
3
Step-by-step solution
Suppose he can fire n bullets per second ∴   Force = Change in momentum per second 144 = n ⁡ × ( 40 1000 ) × ( 1200 ) n ⁡ = 144 × 1000 40 × 1200 n ⁡ = 3