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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NTA Abhyas 2020 · Physics · Center of Mass, Momentum and Collision

A machine gun fires a bullet of mass 40g with a velocity 1200m s ^...

A machine gun fires a bullet of mass 40g40g with a velocity 1200ms−11200m{s}^{- 1}. The man holding it can exert a maximum force of 144N144N on the gun. The maximum number of bullets that the man can fire per second is

Correct answer

3

Step-by-step solution

Suppose he can fire nn bullets per second

∴∴ Force = Change in momentum per second

144=n×(401000)×(1200)144 = n \times ( \dfrac{40}{1000} ) \times ( 1200 )

n=144×100040×1200n = \dfrac{144 \times 1000}{40 \times 1200}

n=3n = 3
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