NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice
A spherical cavity is made in a lead sphere of radius R such that its surface touches the outside surface of lead sphere and passes through the centre. The shift in the centre of mass of the lead sphere as a result of this hollowing, is
Options
- AR 7
- BR 14
- CR 2
- DR
Correct answer
B. R 14
Step-by-step solution
Let centre of mass of lead sphere after hollowing be at point O 2 , where OO 2 = x Mass of spherical hollow m = 4 3 π R 2 2 M 4 2 π R 3 = M 8 and x = OO 1 = R 2 ∴ x = M × 0 - M 8 × R 2 M - M 8 = MR 16 7 M 8 = - R 14 ∴ shift = R 1 4