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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NTA Abhyas 2020 · Physics · Center of Mass, Momentum and Collision

A block of mass 1 kg is pushed towards another block of mass 2 kg...

A block of mass 11 kg is pushed towards another block of mass 22 kg from a 6m6m distance as shown in the figure. If just after the collision, the velocity of 22 kg block is 4ms−14ms^{- 1}, then

A block of mass 1 kg is pushed towards another block of mass 2 kg from a 6m distance as shown in the figure. If just

Options

  1. ACoefficient of restitution between the blocks is 11
  2. BCoefficient of restitution between two blocks is \dfrac{1}{2}
  3. CCoefficient of restitution between two blocks is \dfrac{1}{3}
  4. DCoefficient of restitution between two blocks is \dfrac{1}{4}

Correct answer

A. Coefficient of restitution between the blocks is 11

Step-by-step solution

From conservation of linear momentum we can see that velocity of 11 kg block just after collision is 2m/s2m / s leftwards.

A block of mass 1 kg is pushed towards another block of mass 2 kg from a 6m distance as shown in the figure. If just

A block of mass 1 kg is pushed towards another block of mass 2 kg from a 6m distance as shown in the figure. If just

Now relative velocity of approach = 6m/s6m / s

and relative velocity of separation = 6m/s6m / s

e=Relative velocity of separationRelative velocity of approach=1\text{e} = \dfrac{\text{Relative velocity of separation}}{\text{Relative velocity of approach}} = 1
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