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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

A block of mass 1 kg is pushed towards another block of mass 2 kg from a 6 m distance as shown in the figure. If just after the collision, the velocity of 2 kg block is 4 m s - 1 , then

Options

  1. ACoefficient of restitution between the blocks is 1
  2. BCoefficient of restitution between two blocks is 1 2
  3. CCoefficient of restitution between two blocks is 1 3
  4. DCoefficient of restitution between two blocks is 1 4

Correct answer

A. Coefficient of restitution between the blocks is 1

Step-by-step solution

From conservation of linear momentum we can see that velocity of 1   kg block just after collision is 2   m / s leftwards. Now relative velocity of approach = 6   m / s and relative velocity of separation = 6   m / s e = Relative velocity of separation Relative velocity of approach = 1

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