A bullet is fired from a gun. The force on the bullet is given by F...

Given & $F = 600 - ( 2 \times {10}^{5} t )$

The force is zero at time, t, given by

$0 = 600 - 2 \times {10}^{5} t$

$⇒ t = \dfrac{600}{2 \times {10}^{5}} = 3 \times {10}^{- 3} seconds$

$∴ Impulse = \mathop{∫}_{0}^{t} Fdt = \mathop{∫}_{0}^{3 \times {10}^{- 3}} ( 600 - 2 \times {10}^{5} t ) dt$

$$\begin{array}{ll}= {[ 600t - \dfrac{2 \times {10}^{5} t^{2}}{2} ]}_{0}^{3 \times {10}^{- 3}} \\ = 600 \times 3 \times {10}^{- 3} - {10}^{5} {( 3 \times {10}^{- 3} )}^{2}\end{array}$$

$= 1 . 8 – 0 . 9 = 0 . 9Ns$