Two blocks A and B of equal mass are released on two sides of a...

Acceleration of both the blocks will be $gsin45 °$ or $\dfrac{g}{\sqrt{2}}$ at right angles to each other. Now,



$\overset{→}{a}\text{com} = \dfrac{{m}_{A}\overset{→}{a}\text{A} + {m}_{B}\overset{→}{a}\text{B}}{{m}_{A} + {m}_{B}}$

Here, ${m}_{A} = {m}_{B}$

$∴ {a}_{com} = \dfrac{1}{2} \left({a}_{A} + {a}_{B}\right)</p><p> \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } \text{ and } =\dfrac{1}{2}$ g$\text{ and } \text{ and } (downwards)</p>$