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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

Two blocks A and B of equal mass are released on two sides of a fixed wedge C as shown in the figure. Find the acceleration of the centre of mass of blocks A and B . Neglect friction.

Options

  1. Ag 2 , downwards
  2. Bg , downwards
  3. Cg 2 , upwards
  4. D3 4 g , downwards

Correct answer

A. g 2 , downwards

Step-by-step solution

Acceleration of both the blocks will be g   sin 45 ° or g 2 at right angles to each other. Now, a → com = m A a → A + m B a → B m A + m B Here, m A   =   m B ∴     a com = 1 2 a A + a B = 1 2 g (downwards)

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