Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of $10kgms^{- 1}$ is given to the $5$ kg mass at an angle of $60 °$ to the line joining the masses. The velocity of the $10$ kg mass just after the impulse will be&
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Question

Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of

10kgms^{- 1}

is given to the

5

kg mass at an angle of

60 °

to the line joining the masses. The velocity of the

10

kg mass just after the impulse will be&
&
Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A

Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A

Quantrex Academy · Accepted Answer

Correct answer: B. (1)/(3)ms^ - 1

Apply impulse equation, along string Impulse = 10 × (1)/(2) = (10 + 5)v v = (1)/(3)ms^ - 1

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