A spherical ball A of mass 4 kg , moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v 1 m s – 1 and v 2 m s – 1 respectively making angles of 30 ° and 60 ° with respect to the original direction of motion of A . The ratio v 1 v 2 will be

Step-by-step solution

Applying the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e. along the y-axis), we get. 0   +   0   =   4 v 1   sin   30 °   –   v 2   sin   60 ° 4 v 1 sin   30 °   =   v 2   sin   60 ° v 1 v 2 = sin 6 0 o 4 sin 3 0 o = 3 4