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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

In a one dimensional collision between two identical particles A and B , B is stationary and A has momentum p before impact. During impact B gives an impulse J to A . Then the coefficient of restitution between the two is

Options

  1. A2 J P - 1
  2. B2 J P + 1
  3. CJ P + 1
  4. DJ P - 1

Correct answer

A. 2 J P - 1

Step-by-step solution

Let p 1 and p 2 be the momenta of A and B after collision. Then applying impulse = change in linear momentum for the two particles For B : J = p 1 … ( i ) For A : J = p - p 2 Or p 2 = p - J … ( i i ) Coefficient of restitution e = P 1 - P 2 P = p 1 - p + J p = J - p + J p = 2 J p - 1

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