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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

Two blocks A and B of masses m and 2 m respectively, attached at opposite ends of a spring of constant K , placed on a smooth horizontal surface. Spring is initially at its natural length l . A is given a velocity 2 V 0 and B given velocity V 0 as shown. Maximum separation between m and centre of mass of the system will be:

Options

  1. Al 3 + 8 m V 0 2 3 K
  2. Bl 3 + 2 m V 0 2 3 K
  3. C2 l 3 + 2 m V 0 2 3 K
  4. D2 l 3 + 8 m V 0 2 3 K

Correct answer

D. 2 l 3 + 8 m V 0 2 3 K

Step-by-step solution

l 1 = 2 m l 2 m + m = 2 l 3 K 1 l 1 = K l ⇒ K 1 2 l 3 = K l ⇒ K 1 = 3 K 2 x 1 m a x = m 2 V 0 2 3 K 2 = 8 m V 0 2 3 K d 1 m a x = l 1 + x 1 m a x = 2 l 3 + 8 m V 0 2 3 K

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