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NTA Abhyas JEE Main2020PhysicsCenter of Mass, Momentum and CollisionPractice

Look at the drawing given in the figure which has been drawn with ink of uniform line-thickness. The mass of ink used to draw each of the two inner circles, and each of the two line segments is m. The mass of the ink used to draw the outer circle is 6m. The coordinates of the centres of the different parts are: outer circle (0, 0) left inner circle (−a, a), right inner circle (a, a), vertical line (0, 0) and horizont

Options

  1. Aa 1 0
  2. Ba 8
  3. Ca 1 2
  4. Da 3

Correct answer

A. a 1 0

Step-by-step solution

y CM = m 1 y 1 + m 2 y 2 + m 3 y 3 + m 4 y 4 + m 5 y 5 m 1 + m 2 m 3 + m 4 + m 5 = 6 m 0 + m a + m a + m 0 + m - a 6 m + m + m + m + m = a 1 0

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