NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
A conducting circular loop is placed in a uniform magnetic field 0 . 04   T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2   mm   s - 1 . The induced emf in the loop, when the radius is 2   cm , is
Options
- A4 . 8 π   μV
- B0 . 8 π   μV
- C1 . 6 π   μV
- D3 . 2 π   μV
Correct answer
D. 3 . 2 π   μV
Step-by-step solution
ϕ = BA cos θ = B π r 2 cos 0 ∘ = B π r 2 ε = d ϕ dt = B π 2 r dr dt = 0.04 × π × 2 × 2 × 1 0 - 2 × 2 × 1 0 - 3 = 3.2 π × 1 0 - 6 V = 3.2 π μ V