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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Electromagnetic Induction

NTA Abhyas 2020 · Physics · Electromagnetic Induction

A conducting circular loop of area 2 . 5 × 10 ^ - 3 m ^ 2 and...

A conducting circular loop of area 2.5×10−3m22 . 5 \times {10}^{- 3}{m}^{2} and resistance 10Ω10Ω is placed perpendicular to a uniform time varying magnetic field B(t)=0.6sin⁡(50\pit)TB\left(t\right) = 0.6\sin \left(50\pit\right)T. What is the net charge (in mCmC) flowing through the loop during t=0t = 0 and t=10mst = 10\text{ms}?

Correct answer

1.5

Step-by-step solution

Net charge =ΔϕR=A(B2−B1)R= \dfrac{\Deltaϕ}{R} = \dfrac{A\left({B}_{2} - {B}_{1}\right)}{R}

=(2.5×10−3)(0.6)[sin50π(10)103−sin⁡0]= \left(2 . 5 \times {10}^{- 3}\right) ( 0 . 6 ) \left[sin\dfrac{50\pi ( 10 )}{{10}^{3}} - \sin 0\right]

=1.5×10−3[sinπ2−sin⁡0]= 1 . 5 \times {10}^{- 3}\left[sin\dfrac{\pi}{2} - \sin 0\right]

=1.5×10−3C=1.5mC= 1 . 5 \times {10}^{- 3}C = 1 . 5mC

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