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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Electromagnetic Induction

NTA Abhyas 2020 · Physics · Electromagnetic Induction

A fully charged capacitor C with initial charge Q _ 0 is connected...

A fully charged capacitor CC with initial charge Q0{Q}_{0} is connected to an ideal inductor of self-inductance LL at t=0t = 0. The time at which energy is stored equally between the electric and the magnetic fields is

Options

  1. Aπ4LC\dfrac{\pi}{4}\sqrt{LC}
  2. B2πLC2\pi\sqrt{LC}
  3. CLC\sqrt{LC}
  4. DπLC\pi\sqrt{LC}

Correct answer

A. π4LC\dfrac{\pi}{4}\sqrt{LC}

Step-by-step solution

The charge on the capacitor at any instant of time is

Q=Q0cos⁡(\omegat)Q = {Q}_{0}\cos \left(\omegat\right)

⇒i=dQdt=−ωQ0⇒ i = \dfrac{dQ}{dt} = - \omega{Q}_{0} \sin \left(\omegat\right)

\dfrac{1}{2} Li^{2} = \dfrac{Q2}{2C}</p><p></p><p>{⇒ \d\d dfrac{1}{2}L \left[\oomega{Q}_{0}\sin \left(\omegat\right)\right]}^{2} = [Q0cos⁡(\omegat)]22C\dfrac{\left[{Q}_{0}\cos \left(\omegat\right)\right]2}{2C}

\omega = 1LC\dfrac{1}{LC}

⇒⇒\tan \left(\omegat\right) =$11

\omegat=tan⁡−1(1)=π4\omegat = \tan^{- 1}\left(1\right) = \dfrac{\pi}{4}

t=π4ω=π4LCt = \dfrac{\pi}{4\omega} = \dfrac{\pi}{4}\sqrt{LC}

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