A rectangular frame ABCD made of a uniform metal wire has a straight connection between E & F made of the same wire as shown in the figure.   AEFD is a square of side 1   m & EB = FC = 0 . 5   m . The entire circuit is placed in a steadily increasing uniform magnetic field directed into the plane of the paper. The rate of change of the magnetic field is 1   T   s - 1 , the resistance per unit

Step-by-step solution

e 1 = A d B d t = 1 × 1 × 1 = 1 V e 2   =   0 . 5   V From loop AEFDA ​ 1 I 1 - I 2 - 1 + 3 I 1 = 0 ⇒ 4 I 1 - I 2 = 1                      ...(1) From loop FCBEF 0.5 - 2 I 2 + I 1 - I 2 = 0 ⇒ - I 1 + 3 I 2 = 0.5                      ...(2) From (1) and (2) I 1 = 7 22   A, I 2 = 3 11   A, I 1 - I 2 = 1 22   A I AE = 7 22   A , I BE = 3 11   A , I