NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Electromagnetic Induction
NTA Abhyas 2020 · Physics · Electromagnetic Induction
A conducting loop (as shown) has total resistance R . A uniform...
A conducting loop (as shown) has total resistance . A uniform magnetic field is applied perpendicular to plane of the loop where is a constant and is time. The induced current flowing through loop is
Options
- A\dfrac{\left(b^{2} + a^{2}\right)\gammat}{R}
- B\dfrac{\left(b^{2} - a^{2}\right)\gamma}{R}
- C\dfrac{\left(b^{2} - a^{2}\right)\gammat}{R}
- D\dfrac{\left(b^{2} + a^{2}\right)\gamma}{R}
Correct answer
B. \dfrac{\left(b^{2} - a^{2}\right)\gamma}{R}
Step-by-step solution
Given,
Uniform magnetic field
Total flux,
We know that,
Induced current (i) = \dfrac{\left|e\right|}{R} = \dfrac{\left|\dfrac{dϕ}{\text{ dt }}\right|}{R}<br /><br />From Equation (i),<br /><br />\left(i\right) = \dfrac{\dfrac{d}{dt} [ \gammat\left(b^{2} - a^{2}\right) ]}{R}
Uniform magnetic field
Total flux,
We know that,
Induced current (i) = \dfrac{\left|e\right|}{R} = \dfrac{\left|\dfrac{dϕ}{\text{ dt }}\right|}{R}<br /><br />From Equation (i),<br /><br />\left(i\right) = \dfrac{\dfrac{d}{dt} [ \gammat\left(b^{2} - a^{2}\right) ]}{R}