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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Electromagnetic Induction

NTA Abhyas 2020 · Physics · Electromagnetic Induction

The current through an inductor of impedance 10Ω lags behind the...

The current through an inductor of impedance 10Ω10Ω lags behind the voltage by a phase of 60°60 ° when just the inductor is connected to the ac source. Now the inductor is connected to a 5Ω5Ω resistance in series, then the net impedance of the circuit is

& The current through an inductor of impedance 10Ω lags behind the voltage by a phase of 60 ° when just the inductor is

Options

  1. A15Ω15Ω
  2. B12Ω12Ω
  3. C13.2Ω13.2Ω
  4. D18Ω18Ω

Correct answer

C. 13.2Ω13.2Ω

Step-by-step solution

10 = \sqrt{r^{2} + {X}_L^{2}}andand\dfrac{XL}{r} = \tan 60 °<br/><br/><br /><br />10 = \sqrt{r^{2} + \left(r\sqrt{3}\right)2} or r=5Ω,XL=53Ωr = 5Ω, {X}_{L} = 5\sqrt{3}Ω

Z=(5+5)2+(53)2=175=13.2ΩZ = \sqrt{\left(5 + 5\right)2 + \left(5\sqrt{3}\right)2} = \sqrt{175} = 13.2Ω
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