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A superconducting loop of the radius R has self-inductance L . A uniform and the constant magnetic field B is applied perpendicular to the plane of the loop. Initially current in this loop is zero. The loop is rotated by 180 ° . The current in the loop after the rotation is

Options

  1. Azero
  2. BB π R 2 L
  3. C2 B π R 2 L
  4. DB π R 2 2 L

Correct answer

C. 2 B π R 2 L

Step-by-step solution

Initially, the current was zero, so self-induced flux was also zero. Now when we rotate the loop, the change in flux is Δ ϕ = 2 π R 2 × B Finally, to maintain the same zero flux, the current in the superconducting loop will be such that the flux due to induced current will negative of the flux due to external field L × i = 2 π R 2 × B . i = 2 π R 2 × B L

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