NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
A superconducting loop of the radius R has self-inductance L . A uniform and the constant magnetic field B is applied perpendicular to the plane of the loop. Initially current in this loop is zero. The loop is rotated by 180 ° . The current in the loop after the rotation is
Options
- Azero
- BB π R 2 L
- C2 B π R 2 L
- DB π R 2 2 L
Correct answer
C. 2 B π R 2 L
Step-by-step solution
Initially, the current was zero, so self-induced flux was also zero. Now when we rotate the loop, the change in flux is Δ ϕ = 2 π R 2 × B Finally, to maintain the same zero flux, the current in the superconducting loop will be such that the flux due to induced current will negative of the flux due to external field L × i = 2 π R 2 × B . i = 2 π R 2 × B L