NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
Mutual inductance in the figure shown is -
Options
- AZero
- Bμ 0 b 2 π log e a b
- Cμ 0 b 2 π y log e 1 + b a
- Dμ 0 b 2 π log e 1 + a b
Correct answer
D. μ 0 b 2 π log e 1 + a b
Step-by-step solution
ϕ = M I = ∫ B . d A M I = ∫ a a + b μ 0 I 2 π x × b d x M = μ 0 b 2 π ∫ a a + b d x x M = μ 0 b 2 π log e ⁡ a + b a M = μ 0 b 2 π log e ⁡ 1 + b a