NTA Abhyas JEE Main2020PhysicsElectromagnetic InductionPractice
Two coils have a mutual inductance 0.005 H . The current changes in the first coil according to equation I = I 0 sin ω t , where I 0 = 10 A and ω = 100 π rad s - 1 . The maximum value of emf in the second coil is
Options
- A2 π
- B5 π
- Cπ
- D4 π
Correct answer
B. 5 π
Step-by-step solution
emf, induced in second coil e = M d I d t ⇒ e = M d d t I 0 sin ω t = M I 0 ω cos ω t ⇒ e = 0.005 × 10 × 100 π cos ω t ⇒ e = 5 π cos ω t , e m a x = 5 π (emf is maximum for cos ω t = 1 )