NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Electromagnetic Waves
NTA Abhyas 2020 · Physics · Electromagnetic Waves
The magnetic field of a plane electromagnetic wave is given by → B...
The magnetic field of a plane electromagnetic wave is given by \overset{→}{B} = {B}_{0}\overset{^}{i} \left[\cos \left(kz - \omegat\right)\right] + {B}_{1}\overset{^}{j}\cos \left(kz + \omegat\right), where and . The RMS value of the force experienced by a stationary charge at
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
\overset{→}{B} = {B}_{0}\overset{^}{i} \left[\cos \left(kz - \omegat\right)\right] + {B}_{1}\overset{^}{j}\cos \left(kz + \omegat\right)
Electric filed associated with it is,
\overset{→}{E} = - {B}_{0}c\overset{^}{j}\cos \left(kz - \omegat\right) - {B}_{1}c\overset{^}{i}\cos \left(kz + \omegat\right)
Here, c is speed of light in vacuum.
At
Here is speed of light in vacuum.
0.6N
Electric filed associated with it is,
\overset{→}{E} = - {B}_{0}c\overset{^}{j}\cos \left(kz - \omegat\right) - {B}_{1}c\overset{^}{i}\cos \left(kz + \omegat\right)
Here, c is speed of light in vacuum.
At
Here is speed of light in vacuum.
0.6N