A proton, when accelerated through a potential difference of V = 29 . 6 V , has a wavelength λ associated with it. An α - particle, in order to have the same λ , must be accelerated through a potential difference of how many volts?

Step-by-step solution

λ P = λ α o r h 2 m p Q P V p = h 2 m α Q α V α ∴       m p Q p V p = m α Q α V α ∴        V α = m p m α Q p Q α V p ⇒ V α = 1 4 1 2 × 29 . 6   V = 3 . 7   V