NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
The minimum velocity v with which charge q should be projected so that it manages to reach the centre of the ring starting from the position shown in figure is
Options
- Av = k Q q m R 2 - 2
- Bv = k Q q 2 m R 2 - 2
- Cv = k Q q m R
- Dv = k Q q 2 m R 1 - 2
Correct answer
A. v = k Q q m R 2 - 2
Step-by-step solution
U i + K i = U f + K f k Q q 2 R + 1 2 m v 2 = k Q q R + O 1 2 m v 2 = k Q q R 1 - 1 2 v = 2 k Q q m R 1 - 1 2 v = k Q q m R 2 - 2