NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
Three different types of dielectric slabs have been arranged between the plates of a parallel plate capacitor, as shown in the figure. The equivalent capacitance of the system between the points P and Q will be
Options
- AK ε 0 A d
- B2 K ε 0 A d
- C3 K ε 0 A d
- D3 K ε 0 A 2 d
Correct answer
C. 3 K ε 0 A d
Step-by-step solution
C 1 = ( 2 K ) ε 0 A 2 d ,   C 2 = ( 3 K ) ε 0 A d ,   C 3 = ( 6 K ) ε 0 A d C e q = C 1 + C 2 C 3 C 2 + C 3 = 3 K ε 0 A d