The plates of a parallel plate capacitor are charged to a potential of 200 V . Now, a dielectric slab of thickness 4 mm is inserted between its plates and to maintain the same potential difference between the plates of the capacitor, the di

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The plates of a parallel plate capacitor are charged to a potential of 200 V . Now, a dielectric slab of thickness 4 mm is inserted between its plates and to maintain the same potential difference between the plates of the capacitor, the distance between the plates is increased by 3.2 mm . The dielectric constant of the slab is

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Correct answer: C. 5

ε 0 A d = ε 0 A d ′ - t + t K ⇒ d = d ′ - t + t K ⇒ d ′ - d = t 1 - 1 K Here, d ′ - d = 3 .2 mm , t = 4 mm ∴ 3 .2 = 4 1 - 1 K ⇒ 3 .2 4 = 1 - 1 K ⇒ 1 - 1 K = 4 5 ∴ K = 5

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