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The figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is the same at all points on this curve and is equal to E . If the potential at A is V , then the potential at B is

Options

  1. AV - E R θ
  2. BV - 2 E R sin ⁡ θ 2
  3. CV + E R θ
  4. DV + 2 E R sin ⁡ θ 2

Correct answer

A. V - E R θ

Step-by-step solution

V A - V B = Work done by the electric field per unit charge. Work done from A to B = E R θ ∴ V B = V A - E R θ = V - E R θ

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