NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
A ring of charge with radius 0.5 m has 0.002 π m gap. If the ring carries a charge of +1 C, the electric field at the centre is
Options
- A7.5 × 10 7 N C - 1
- B7.2 × 10 7 N C - 1
- C6.2 × 10 7 N C - 1
- D6.5 × 10 7 N C - 1
Correct answer
B. 7.2 × 10 7 N C - 1
Step-by-step solution
Approaximate charge on the element opposite to the gap is Δ q = Q 2 π r 0.002 π = 1 2 π 0.5 × 2 π 1000 = 2 × 10 - 3 C E = 9 × 10 9 × 2 × 10 - 3 0.5 2 = 7.2 × 10 7 N C - 1