NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
In the given figure the work done by the battery after the switch S is closed is
Options
- A1 0 0 μ J
- B- 1 0 0 μ J
- C8 0 μ J
- D- 8 0 μ J
Correct answer
C. 8 0 μ J
Step-by-step solution
Before the switch S is closed Q i = C eq V = 5 × 4 = 2 0 μ C When the switch S is closed Q f = CV = 1 0 × 4 = 4 0 μ C W cell = Δ QE = Q f - Q i × E = 2 0 × 4 = 8 0 μ J