NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
Plates of a parallel plate capacitor, having a potential difference 100 V applied across them, carry a surface charge density of 50 nC c m - 2 . Spacing between the plates is
Options
- A329 μ m
- B259 μ m
- C177 μ m
- D125 μ m
Correct answer
C. 177 μ m
Step-by-step solution
E = σ ε 0 Potential difference V = E d ∴ d = V E = 100 50 × 10 - 7 × 8.85 × 10 - 12 = 177 × 10 - 6   m = 177   μm