NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
In the given diagram, there is a conducting sphere of radius r 1 which is surrounded by a dielectric of relative permittivity ε r . If conducting sphere is given charge q , then the surface density of polarization charges, on the outer surface of the dielectric layer, is
Options
- Aε r q 4 π r 2 2
- Bq 4 π ε r r 2 2
- C( ε r - 1 ) q 4 π r 2 2
- D( ε r - 1 ) q 4 π ε r r 2 2
Correct answer
D. ( ε r - 1 ) q 4 π ε r r 2 2
Step-by-step solution
Induced charge = q 1 - 1 ε r Surface density = q 1 - 1 ε r 4 π r 2 2 = q ε r - 1 4 π ε r r 2 2