Five equal point charges with q = 10 nC are located at x = 2 , 4 , 5 , 10 and 20 m . Taking the value of permittivity of free space ε 0 = 1 36 π × 10 - 9 C 2 N - 1 m - 2 and potential at infinity to be zero, calculate the potential (in V ) at x = 0 ?

Step-by-step solution

Given q = 10   nC   =​ 10 × 10 - 9   C The potential at the point x = 0 , will be the sum of potential produced by the charges placed at x = 2 ,   4 ,   5 ,   10 and 20   m Potential, V = q 4 π ε 0 × r Then, V 1 = q 4 π ε 0   ×   2 V 2 = q 4 π ε 0 × 4 V 3 = q 4 π ε 0 × 5 V 4 = q 4 π ε 0 × 10 V 5 = q 4 π × 20 The resultant potential, V = V 1 + V 2 + V 3 + V 4 + V 5 = q 4 π