NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice

The total electrostatic energy stored in both the capacitors (in μ J ) is

Correct answer

Step-by-step solution

According to circuit diagram, capacitors are connected in series combination. So, equivalent capacitance C e q = 3 × 6 3 + 6 = 18 9 = 2 μ F We know that, Total electrostatic energy U = 1 2 C e q V 2 = 1 2 × 2 × - 3 2 = 9 μ J

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