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Two thin rings each of radius R are placed at a distance d apart. The charges on the rings are + q and − q . The potential difference between their centres will be -

Options

  1. Aq R 4 π ε 0 d 2
  2. Bq 2 π ε 0 1 R - 1 R 2 + d 2
  3. Cz e r o
  4. Dq 4 π ε 0 1 R - 1 R 2 + d 2

Correct answer

B. q 2 π ε 0 1 R - 1 R 2 + d 2

Step-by-step solution

V A = k q R - k q R 2 + d 2 V B = - k q R - + + k 2 R 2 + d 2 - ∴ V A - V B = 2 k q R - 2 k q R 2 + d 2 ∴ V A - V B = q 2 π ε 0 1 R - 1 R 2 + d 2

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