NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
The quarter disc of radius R (see figure) has a uniform surface charge density σ . Find electric potential at a point O , O , Z .
Options
- Aσ 8 ϵ 0 1 - Z R 2 + Z 2
- Bσ 4 ϵ 0 R 2 + Z 2 + Z
- Cσ 8 ϵ 0 R 2 + Z 2 - Z
- Dσ 8 ϵ 0 1 + Z R 2 + Z 2
Correct answer
C. σ 8 ϵ 0 R 2 + Z 2 - Z
Step-by-step solution
V = ∫ 0 R k α π r d r α r 2 + z 2 = σ 8 ϵ 0 ∫ 0 R r d r r 2 + z 2 t 2 = r 2 + z 2 t d t = r d r V = σ 8 ϵ 0 ∫ z 2 2 + R 2 d t = σ 8 ϵ 0 R 2 + z 2 - z