NTA Abhyas JEE Main2020PhysicsElectrostaticsPractice
A small conducting sphere of the radius r is lying concentrically inside a bigger hollow conducting sphere of radius R . The bigger and smaller sphere are charged with Q and q ( Q > q ) and are insulated from each other. The potential difference between the sphere will be
Options
- A1 4 π ε 0 q r – q R
- B1 4 π ε 0   q R – Q r
- C1 4 π ε 0   q r – Q R
- D1 4 π ε 0   Q R + q r
Correct answer
A. 1 4 π ε 0 q r – q R
Step-by-step solution
Potential of the inner sphere V A = k q r + k Q R Potential of the outer sphere V B = k q R + k Q R ∴ V A – V B = k q r – k q R = 1 4 π ε 0 q r - Q R