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A hollow charged metal sphere has radius r . If the potential difference between its surface and a point at distance 3 r from the centre is V , then the electric field intensity at distance 3 r from the centre is

Options

  1. AV 6 r
  2. BV 4 r
  3. CV 3 r
  4. DV 2 r

Correct answer

A. V 6 r

Step-by-step solution

V A - V B = kQ r - kQ 3 r = V = 2 kQ 3 r E = k Q 3 r 2 = k Q 9 r 2 ⇒ E = V 6 r

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