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NTA Abhyas JEE Main2020PhysicsGravitationPractice

The mass and the diameter of a planet are three times of the respective values for the earth. If the time period of oscillation of a simple pendulum on earth is 2   s , then the time period of oscillation of the same pendulum on the surface of the given planet would be

Options

  1. A3 2   s
  2. B2 3   s
  3. C3 2   s
  4. D2 3   s

Correct answer

D. 2 3   s

Step-by-step solution

We know that, g = G M R 2 ⇒ g p g e = M p M e × R e R p 2 = 3 × 1 9 = 1 3 Also, T = 2 π 1 g ⇒ T p T e = g e g p = 3 ⇒ T p = 3 T e Time period at earth for seconds pendulum = 2   s ∴ T p = 2 3   s

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