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NTA Abhyas JEE Main2020PhysicsGravitationPractice

The escape velocity from the earth is about 11 k m s - 1 . The escape velocity from a planet having twice the radius and the same mean density as the earth is

Options

  1. A22   k m   s - 1
  2. B11   k m   s - 1
  3. C5.5   k m   s - 1
  4. D15.5   k m   s - 1

Correct answer

A. 22   k m   s - 1

Step-by-step solution

v = 2 GM R = 2 G 4 3 πR 2 d v   ∝   R d v = 2 v 0

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