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NTA Abhyas JEE Main2020PhysicsGravitationPractice

Two point masses M are kept fixed on the x -axis at a distance a from the origin, another point mass m is moving in a circular path of radius R (in y - z plane) under the influence of gravitational force of attraction, then speed of m will be (Assume no forces are acting on m other than the gravitational forces by two M )

Options

  1. A2 G M R 2 R 2 + a 2 3 2
  2. BG M R 2 R 2 + a 2 3 2
  3. C3 G M R 2 R 2 + a 2 3 2
  4. D5 G M R 2 R 2 + a 2 3 2

Correct answer

A. 2 G M R 2 R 2 + a 2 3 2

Step-by-step solution

F R = 2 F sin ⁡ θ m v 2 R = 2 G M m r 2 R r r = a 2 + R 2 ⇒ v = 2 G M R 2 R 2 + a 2 3 2

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