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NTA Abhyas JEE Main2020PhysicsGravitationPractice

A , B , C and D are four particles with each of mass M lying on the vertices of a square of side a . They always move along a common circle with velocity v under mutual gravitational force. Find v so that they always remain on the vertices of the square

Options

  1. AG M 2 2 + 1 2 2 a
  2. BG M 2 + 1 2 a
  3. CG M 2 2 + 1 a
  4. Dnone

Correct answer

A. G M 2 2 + 1 2 2 a

Step-by-step solution

From the above figure, it is clear that F n e t = 2 F 1 + F 3 = M V 2 R F 1 = F 2 2   G M 2 a 2 + G M 2 a 2 2 = M v 2 a / 2 v = G M 1 + 2 2 2 2 a

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