If the escape speed of a projectile on Earth's surface is 11 . 2 km s - 2 and a body is projected out with thrice this speed, then determine the speed of the body far away from the Earth

Step-by-step solution

According to the principal of conservation of energy, Initial kinetic energy + initial potential energy, = final kinetic energy + final potential energy ⇒               1 2 m v 2 - G M m R = 1 2 m v ′ 2 + 0 ⇒                   1 2 m v ′ 2 = 1 2 m v 2 - G M m R ..... (i) As consider, v e = escape velocity 1 2 m v e 2 = G M m R ........ (ii) ∴       From equation (i) and (ii), we get 1 2 m v &#