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NTA Abhyas JEE Main2020PhysicsGravitationPractice

Two identical satellites are moving around the earth in circular orbits at heights 3 R and R respectively where R is the radius of the Earth. The ratio of their kinetic energies is

Options

  1. A2 : 1
  2. B1 : 2
  3. C3 : 1
  4. D2 : 3

Correct answer

B. 1 : 2

Step-by-step solution

The kinetic energy of satellites in a circular orbit is given as E k = G M m 2 r ⇒   E k 1 E k 2 = r 2 r 1 = R + R R + 3 R = 2 R 4 R = 1 2

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