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NTA Abhyas JEE Main2020PhysicsGravitationPractice

Two particles having masses m and 4 m are separated by distance l . The distance of the centre of mass from m is x 1 and x 2 is the distance of point at which gravitational field intensity is zero. Find the value of x 1 x 2

Options

  1. A1
  2. B2
  3. C2.4
  4. D3.6

Correct answer

C. 2.4

Step-by-step solution

x 1 = 4 m l 5 m = 0.8 l G m x 2 2 = 4 G m ( l - x 2 ) 2 2 x 2 + x 2 = l x 2 = l 3 x 1 x 2 = 2.4

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