NTA Abhyas JEE Main2020PhysicsGravitationPractice
The weight of a body on the surface of the earth is 63 N . What is the gravitational force on it due to the earth at a height equal to half the radius of earth?
Options
- A28   N
- B23   N
- C12   N
- D67   N
Correct answer
A. 28   N
Step-by-step solution
Given h = R ⁡ e ⁡ 2 Acceleration due to gravity at altitude h is given by g ′ = g 1 + h ⁡ R ⁡ e ⁡ 2 = g 1 + R ⁡ e ⁡ / 2 R ⁡ e ⁡ 2 = g 1 + 1 2 2 = g 3 / 2 2 = g' = 4 9  g ...(i) Weight of the body at earth's surface w = m g = 63   N ...(ii) Weight of the body at altitude h = R e 2 w ⁡ ′ = m g ⁡ ′ = 4 9 mg ...(iii) Using Eq. (ii), we get w ⁡ ′ = 4 9 × 6 3 w ' = 28   N