NTA Abhyas JEE Main2020PhysicsGravitationPractice
An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of escape velocity from the earth. The height of satellite above the surface of earth is -(where R = r a d i u s o f e a r t h )
Options
- AR
- B2 R
- C3 R
- D4 R
Correct answer
A. R
Step-by-step solution
escape velocity V s = 2 G m R orbital velocity V 0 = G m r given V 0 = 1 2 V e ⇒ G m R + h = 1 2 2 G m R ⇒ R + h = 2 R or h = R