NTA Abhyas JEE Main2020PhysicsMagnetic Effects of CurrentPractice
A rod of mass m and length 2 l is connected to two massless strings as shown in figure. A wooden disk of same mass m is fixed at the mid-point of the rod in such a way that the plane of disk is perpendicular to the rod. A massless wire is wrapped around disk and having current I . There is vertically upward magnetic field B at the location of disk. (Sense of current in the loop when seen from string A side is clockwi
Options
- Am g + I π R 2 B 2 l
- Bm g - I π R 2 B 2 l
- Cm g
- D2 m g
Correct answer
A. m g + I π R 2 B 2 l
Step-by-step solution
net torque about disc is zero T A ×l = T B ×l + I π R 2 B And T A + T B = 2 m g ⇒ T A = m g + I π R 2 B 2 l