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A wire is tightly wound to form of a spiral of N turns with the inner and outer radii equal to a and b respectively. When a current I is established in the coil, the magnetic field at the centre is

Options

  1. Aμ 0 N I b
  2. Bμ 0 N I a
  3. Cμ 0 N I 2 b - a ln b a
  4. Dμ 0 N I b - a ln b a

Correct answer

C. μ 0 N I 2 b - a ln b a

Step-by-step solution

An element is assumed at distance x from center whose width is d x . No. of turns in width b - a = N ∴ No. of turns is width d x = n = N b - a d x d B = μ 0 n i 2 x = μ 0 i N 2 b - a d x x ∴ B = μ 0 i N 2 b - a ∫ a b d x x = μ 0 N i 2 b - a log e ⁡ b a

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