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The figure shows a current-carrying square loop ABCD of side 10 cm and current i = 10 A . The magnetic moment M → of the loop is

Options

  1. A0.05 i ^ - 3 k ^ A m 2
  2. B0.05 j ^ + k ^ A m 2
  3. C0.05 3 i ^ + k ^ A m 2
  4. Di ^ + k ^ A m 2

Correct answer

A. 0.05 i ^ - 3 k ^ A m 2

Step-by-step solution

Areal vectors will be ⊥ to the plane. Area vector is at 6 0 o angle with x-axis and 3 0 o angle with -z-axis. M → = NI A → M → = 1 0 × 1 0 - 2 A m 2 M = 0 · 1 A m 2 M → = M x i ^ - M z k ^ = Mcos 60 i ^ - Mcos 30 o k ^ M → = 0.05 i ^ - 3 k ^

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