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The figure shows a current-carrying loop, some part of which is circular and some part is a line segment. The magnetic induction at the centre is

Options

  1. A3 μ 0 Iπ 4 a
  2. Bμ 0 I 4 π a 1 + π
  3. Cμ 0 I 8 π a
  4. D3μ 0 I 8 a

Correct answer

D. 3μ 0 I 8 a

Step-by-step solution

The magnetic field due to circular arc is ​ B = μ 0 I α 4 π r = μ 0 I 4 π a ( 3 π 2 ) = 3 μ 0 I 8 a

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